Simple Python solution

• This solution loops through all of the values in the nums array and appends it to a temp array. Once that temp array has the length of c, it appends that to another array I call, "result."

I reset the count for c to 0 and I continue doing this until all of the values are recreated in the "result" array.

There's also a conditional to check if the areas match for both the current and reshaped array.

I haven't looked at other solutions yet and this is my first attempt.

``````class Solution(object):
def matrixReshape(self, nums, r, c):
"""
:type nums: List[List[int]]
:type r: int
:type c: int
:rtype: List[List[int]]
"""

if (r * c) != len(nums) * len(nums[0]):
return nums

result = []
temp = []
count = 0
for i in range(len(nums)):
for j in range(len(nums[0])):
# create an array with length of c
temp.append(nums[i][j])
count += 1
if count == c:
# append the array to the result array
# this makes sure it has the new c length
result.append(temp)
temp = []
count = 0

return result
``````

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