Beats 95% of Python solutions...

  • 0

    Very simple and calls less if conditions:

    class Solution(object):
        def islandPerimeter(self, grid):
            :type grid: List[List[int]]
            :rtype: int
            perim = 0
            for i in range(len(grid)):
                for j in range(len(grid[0])):
                    if grid[i][j] == 1:
                        perim += 4
                        if (i>=1) and grid[i-1][j] == 1:
                            perim -= 2
                        if (j>=1) and grid[i][j-1] == 1:
                            perim -= 2
            return perim

  • 0

    cool! It was one of the most simple python solution I've seen.By the way, do you konw the time and space complexity? Is O(n^2) ?

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