Java AC Easy Solution


  • 0
    W
        public String reverseWords(String s) {
            String[] parts = s.split(" ");
            StringBuilder sb = new StringBuilder();
            for (int i = parts.length - 1; i >= 0; i--) {
                if (parts[i].length() == 0 || parts[i].equals(" ")) continue;
                sb.append(parts[i]);
                sb.append(" ");
            }
            return sb.toString().trim();
        }
    

  • 0
    R

    I don't think you need the check for whether or not a token in parts is a space, because splitting on space means that all spaces are either not present or represented by an empty string in the resulting token array. Correct me if I'm wrong?


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