Java no bit-wise really easy to understand 1 line solution 3 ms

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    public boolean isPowerOfFour(int num) {
        return num>0 && Integer.highestOneBit(num) == num && Integer.numberOfTrailingZeros(num) % 2 == 0;

    As long as we know if the number is power of 4 then it has 1 bit at highest position and following with even number of 0s, then it comes with this idea. Very straight forward and no need to convert it to string.

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