Easiest Solution With Explanation

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    [alt text](image url)0_1497347622870_string.jpg
    Guys As i have found most difficulties to understand the problem.Here From the above picture we can see that the product of ith and jth number will be stroed in position i+j and i+j+1,
    i.e., res[i+j] is used to store the carry value and res[i+j+1] is used to rightmost digit of the sum.
    0_1497347660069_Screenshot (99).png
    I hope it will help you.

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