Concise MySQL solution with reference

  • 2
    # Refer to:
      select num
      from number
      group by num
      having count(*) = 1
      order by num desc limit 1
    ) as num;

  • 0

    Same idea

    select max(a.num) as num
    from (select num from number group by num having count(*)=1) as a

  • 0

    Actually the first solution is much faster than the solution above. They are different. The second one uses a derived table while the first one does not. the first one beats about 85% but the second one only beats about 45%. BTW, it is a very clever idea to transform empty values to NULL using the first solution.

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