# Beats 100% of other Java solutions. Easy-to-understand explanation.

• ``````public class Solution {
int count = 0;
public int pathSum(TreeNode root, int sum) {
if(root == null) return 0;
int depth = findDepth(root);
int[] pathArray = new int[depth];
helper(root, sum, pathArray, 0, depth);
return count;
}

public void helper(TreeNode root, int total, int[] nums, int level, int depth) {
if(root == null) return;
if(level >= depth) return;
nums[level] = root.val;
int sum = 0;
for(int i = level; i>=0; i--) {
sum += nums[i];
if(sum == total)
count++;
}
helper(root.left, total, nums, level + 1, depth);
helper(root.right, total, nums, level + 1, depth);
}

public int findDepth(TreeNode root) {
if(root == null) return 0;
int left = findDepth(root.left);
int right = findDepth(root.right);
return Math.max(left, right) + 1;
}
``````

Intuition behind the solution:

• Since the paths do not necessarily start or end at the root or a leaf, check the sum of a given path starting from a given node, upwards to the root.

• For checking the sum, have an array that represents a given path. The array would be of the size of the tree ( `findDepth()` essentially computes the height of the tree to hold all nodes from the root to the leaf for the longest path).

• Traverse on both sides of the tree and find the corresponding sum along the different paths.

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