Simple Javascript Solution


  • 1
    R

    Would love some feedback on more efficient implementations, but here is a pretty straight forward approach using a hash map.

    
    var singleNumber = function(nums) {
        let hash = {};
        for (let i = 0; i < nums.length; i++) {
            !hash.hasOwnProperty(nums[i]) ? hash[nums[i]] = nums[i] : delete hash[nums[i]];
        }
        return parseInt(Object.keys(hash)[0]);
    };
    
    

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