Python 45 chars , 1 line solution

  • 0

    This problem begs to count the # chars not the lines.

    class Solution(object):
        def reverseWords(self, s):
            :type s: str
            :rtype: str
            return " ".join([s[::-1] for s in a.split()])

  • 1

    If you want to optimize for #chars, you could use a generator expression (and omit its parentheses) instead of a list comprehension.

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