Java solution explained in detail

  • 0
    public class Solution {
        public int maxProfit(int[] prices) {
            if(prices.length==0) return 0;
            int min = prices[0];
            int maxProfit = 0;
            int currMaxProfit = 0;
            for(int i=1;i<prices.length;i++) {
                //if the current price is greater than min and also greater than previous day's price,
                //get the max profit since this is an increasing sequence of prices. 
                if(prices[i] > min && prices[i] > prices[i-1]) {
                    currMaxProfit = Math.max(currMaxProfit, prices[i]-min);
                //otherwise, the min price will be the latest price and the profit earned so far is added to the total profit.
                //currProfit is set to 0 and will be calculated for the next increasing sequence.
                    min = prices[i];
                    maxProfit += currMaxProfit;
                    currMaxProfit = 0;
            return maxProfit+currMaxProfit;

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