Java accepted solution solved Integer.MIN_VALUE problem


  • 2
    I
    public class Solution {
        public double myPow(double x, int n) {
            if(n == 0) return 1;
            if(n < 0) {
                if(n == Integer.MIN_VALUE) {
                   x = x * x;
                   n = n / 2;
                }
                n = -n;
                x = 1.0 / x;
            }
            return n % 2 == 0 ? myPow(x*x, n / 2) : x* myPow(x*x, n / 2);
        }
    }
    

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