# 79ms runtime C++ program

• ``````class Solution {
public:
// measure the length of each list;
int lenA = 0, lenB = 0;
while (pointA != NULL) {
lenA++;
pointA = pointA -> next;
}
while (pointB != NULL) {
lenB++;
pointB = pointB -> next;
}
// refresh pointA and pointB;
// if the lengths are different, "cut" the longer one;
if (lenA > lenB) {
// cut A
int n = lenA - lenB;
while(n) {
pointA = pointA -> next;
n--;
}
}
if (lenA < lenB) {
// cut B
int n = lenB - lenA;
while(n) {
pointB = pointB -> next;
n--;
}
}
// if the lengths are the same, two pointers starts from each list's head and compare, finding the intersection;
while (pointA != NULL && pointB != NULL) {
if (pointA -> val == pointB -> val && pointA -> next == pointB -> next) {
return pointA;
}
pointA = pointA -> next;
pointB = pointB -> next;
}
// if searched the whole list while no intersections are found, return NULL
return NULL;
}
};``````

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