**Solution**

**Compare Version Numbers** https://leetcode.com/problems/compare-version-numbers/?tab=Description

- The only thing to consider is that a version may have zero or more ".". We can have "3.2.5.6.7".

```
class Solution(object):
def get_version(self, v):
if "." in v:
output = v.split(".")
return [int(x) for x in output]
else:
return [int(v)]
def compareVersion(self, version1, version2):
"""
:type version1: str
:type version2: str
:rtype: int
"""
v1 = self.get_version(version1)
v2 = self.get_version(version2)
N = max(len(v1), len(v2))
for i in range(N):
m_1 = v1[i] if i < len(v1) else 0
m_2 = v2[i] if i < len(v2) else 0
if m_1 > m_2:
return 1
elif m_1 < m_2:
return -1
return 0
```