# C++ solution

• ``````//Reference :
class Solution {
public:
// The keypoint is how to make sure that we can halve n as many times as possible.
// Put it in another way, we want to divede n by 2 as many times as possible.
// Which means, if there is any chance that we can convert n to be multiple of 4,
// we should do that without hesitation.
// The only exception is number 3, since the only reason we convert n to be muptile of 4
// is that we can "divide n by 4" in our recursion path.
int integerReplacement(int n) {
// we know the input is always positive
if (n==1) return 0;
if (n == INT_MAX)
return 32;
if (n==3) return 2;
if (n%2==0) {
return 1+integerReplacement(n/2);
} else {
if ( (n+1)%4==0) {
return 1 + integerReplacement(n+1);
} else {
return 1 + integerReplacement(n-1);
}
}
}
};
``````
``````class Solution {
public:
// The keypoint is how to make sure that we can halve n as many times as possible.
// Put it in another way, we want to divede n by 2 as many times as possible.
// Which means, if there is any chance that we can convert n to be multiple of 4,
// we should do that without hesitation.
// The only exception is number 3, since the only reason we convert n to be muptile of 4
// is that we can "divide n by 4" in our recursion path.
int integerReplacement(int n) {
if (n==INT_MAX) return 32;
// we know the input is always positive
int count(0);
while(n!=1) {
if (n%2==0) {
n /= 2;
} else {
if ( (n+1)%4==0 && n>4) {
++n;
} else {
--n;
}
}

++ count; // increase replacement count
}
return count;
}
};
``````

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