# My easy to understand java solution

• ``````public String countAndSay(int n) {

String prev_no = "1";
//traverse till the nth number
for(int i = 1; i < n; i++){
//generate current number from its previous number
char[] s = prev_no.toCharArray();
//store current number here
String currNo = "";
//get first digit from the previous number starting from right
int p = Integer.parseInt("" + s[0]);
int count = 1;

//traverse from 2nd till end digit
for(int j = 1; j < s.length; j++){
//if previous digit is same as current
if(p == Integer.parseInt("" + s[j]))
count++;
else{
//add the previous digit with its count to current number
currNo += Integer.toString(count) + Integer.toString(p);
p = Integer.parseInt("" + s[j]);
count = 1;
}
}
//add the final digit and its count to current number
currNo += Integer.toString(count) + Integer.toString(p);
//assign previous with this current number
prev_no = currNo;
}
return prev_no;
}
'''``````

Looks like your connection to LeetCode Discuss was lost, please wait while we try to reconnect.