Accepted and simple recursive python solution


  • 0
    A
    if l1 is None:
                return l2
            
            if l2 is None:
                return l1
            
            if l1.val <= l2.val:
                l1.next = self.mergeTwoLists(l1.next,l2)
                return l1
            if l2.val <= l1.val:
                l2.next = self.mergeTwoLists(l1,l2.next)
                return l2
    

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