Dividing by central axes to rorate in place


  • 0
    O

    Instead of dividing the matrix by diagonal, I divide it into 4 pieces by central axes. Then do the transform:

    class Solution {
    public:
    void rotate(vector<vector<int> > &matrix) {
        int n = matrix.size();
        for (int i = 0; i < (n + 1) / 2; i++)
        {
            for (int j = 0; j < n / 2; j++)
            {
                int temp = matrix[i][j];
                matrix[i][j] = matrix[n - 1 - j][i];
                matrix[n - 1 - j][i] = matrix[n - 1 - i][n - 1 - j];
                matrix[n - 1 - i][n - 1 - j] = matrix[j][n - 1 - i];
                matrix[j][n - 1 - i] = temp;
            }
        }
    }
    };

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