# My solution is below

• ``````class Solution {
public:
int titleToNumber(string s) {
int result = 0;
for (int i = s.size() - 1; i >= 0; i--)
result += (s[i] - 'A' + 1) * pow(26, s.size() - 1 - i);
return result;
}
};``````

• Hey, here is my solution, I think we have the same idea, is there a better solution?

``````public int titleToNumber(String s) {
if(s == null || s.length() <= 0){
return 0;
}
byte[] b = s.getBytes();
int sum = 0;
for(int i = 0 ; i < b.length ; i++){
sum += (b[i] - 64)*Math.pow(26, b.length - i - 1);
}
return sum;
}
``````

• I like intuitive solution, because it can be understood easily, maybe it is not a better solution. The solution using too much skills is more difficult to understand than common solution.

• Hi, I have the same habit to check some special cases in the begin, like s ==null.
But I don't get it why there is also "s.length() <= 0". Could you explain that, maybe give me some examples? Thanks a lot!

• If the parameter s is equal to "",the result will be what ？

• yes, it explains s.length() = 0, now what about the situation where the length is less than 0?
Thanks

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