What if different sequences of the same numbers are counted as the same combination?

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    I thought the question was asking how many combinations where the order does not matter.
    For example, if target=5, nums=[2, 3], then the number of combinations should be 1 because (2, 3) and (3, 2) represent the same combination.
    If this is the case, how to solve this problem?

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    This post is deleted!

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    @opmiss You can still use DP, but slightly different loops. Think about the coin change problem. To reach an mount, how many combinations (real combinations, not permutations) you can have.

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