Short Javascript using Greedy

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    function sortNumber(a,b)
        return a[0] === b[0]? a[1] - b[1]: b[0] - a[0];
    var reconstructQueue = function(people) {
        var sorted = [];
        for(var i = 0; i < people.length; i++){
            sorted = sorted.pushQueue(people[i]);
        return sorted;
    Array.prototype.pushQueue = function(n){
        return this;

    The idea is always put the tallest one to the array, if more than one people with same height, put the one with less second number first.

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