Simple C++ 28ms solution


  • 0
    S
    bool canConstruct(std::string ransomNote, std::string magazine)
    {
      int noteLen = ransomNote.length();
      int magLen = magazine.length();
      //Some special cases to return immediately
      if (magLen < noteLen) return false;
      if (magLen == noteLen && ransomNote==magazine) return true;
      //Since we are only dealing with lowercase letters
      int noteContents[26] = {0};
      int magContents[26] = {0};
      //Each characters count for both strings
      for (int i = 0; i < noteLen; i++) noteContents[ransomNote[i]-'a']++;
      for (int i = 0; i < magLen; i++)  magContents[magazine[i]-'a']++;
      //If ransom string had any character count more than magazine, we can return false
      for (int i = 0; i < 26; i++) if (noteContents[i] > magContents[i]) return false;
      //If nothing has been returned yet, result must be true because we have checked for all false cases
      return true;
    }
    

    Edit: I agree with @ameyd. Hence removed the initial check to false if both string have same size. Thank you @ameyd


  • 1
    A

    Your solution would fail for canConstruct("ab", "ba"). Expected answer is True.


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