Simple Python solution based on Predecessor and Successor

  • 0
    class Solution(object):
        def closestValue(self, root, t):
            def close(root, t, pred, succ):
                if not root:
                if root.val == t:
                    pred[0] = succ[0] = root.val
                if t < root.val:
                    succ[0] = root.val
                    close(root.left, t, pred, succ)
                    pred[0] = root.val
                    close(root.right, t, pred, succ)
            pred, succ = [float('inf')], [float('inf')]
            close(root, t, pred, succ)
            pred, succ = pred[0], succ[0]
            return pred if abs(pred - t) <= abs(succ - t) or pred == succ else succ

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