Python esay to understand

  • 2
    class Solution(object):
    def isSymmetric(self, root):
        :type root: TreeNode
        :rtype: bool
        if root is None:
            return True
        return self.isS(root.left, root.right)
    def isS(self, left, right):
        if left is None and right is None:
            return True
        elif left is None or right is None:
            return False
        if left.val != right.val:
            return False
        return self.isS(left.left, right.right) and self.isS(left.right, right.left)

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