Java solution using String manipulation


  • 0
    A
    public int[] countBits(int num) {
            
            int[] res=new int[num+1];
            
            for(int i=num;i>=0;i--)
            {
                String temp=Integer.toBinaryString(num);
                temp=temp.replace("0","");
                res[i]=temp.length();
            }
            
            return res;
            
        }
    
    • Using Integer.toBinaryString gets every number's binary representation
    • Using String.replace() to eliminate all the "0" characters
    • The length of left string is the number of 1's

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