My AC 7 lines solution in C++ slow but easy to read

  • 0
    vector<int> maxSlidingWindow(vector<int>& nums, int k) {
        if(nums.empty()) return {};
        vector<int> res;
        int n=nums.size()-k+1;
            for(int i=0;i<n;i++) res.push_back(*max_element(nums.begin()+i,nums.begin()+i+k));
        return res;
    • step1: calculate the size of the result-> nums.size()-k+1;
    • step2: select the max value in each k subarray of nums;

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