Short python solution

  • 7
    # Definition for a binary tree node.
    # class TreeNode(object):
    #     def __init__(self, x):
    #         self.val = x
    #         self.left = None
    #         self.right = None
    class Solution(object):
        def levelOrderBottom(self, root):
            :type root: TreeNode
            :rtype: List[List[int]]
            answ, L = [], [root]
            while L and root:
                answ.insert(0,[n.val for n in L])
                L = [ C for N in L for C in (N.left,N.right) if C ]
            return answ

  • 2
    class Solution(object):
        def levelOrderBottom(self, root):
            res, nodes = [], [root] if root else []
            while nodes:
                res.append(list(node.val for node in nodes))
                nodes = [x for node in nodes for x in (node.left, node.right) if x]
            return res

  • 0

    Hello, will you be able to explain what happens during the while loops? how do you change the level of the tree (if [3, 9, 20, null, null, 15,7]) from first level [3] to second level [9,20]? it seen like after the nest for loop the level auto change to the next level?

  • 0
    This post is deleted!

  • 0

    @cygnx Not sure why this has up votes considering insert at 0 is O(n) operation. It would've made more sense to do the same the first level order problem and just reverse the answer...that would've been faster

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