# Easy and Simple to Understand Java Solution

• I used a HashMap to store the frequency of each digit and count1 gives us the Bull count and count2 gives us the Cows count

`````` public class Solution {
public String getHint(String secret, String guess) {
char arr1[] = secret.toCharArray();
char arr2[] = guess.toCharArray();
if(arr1.length == arr2.length)
{
int count1=0,count2=0;
StringBuffer result = new StringBuffer(arr1.length);
HashMap<Character,Integer> hmap = new HashMap<Character,Integer>();
for(int i=0;i<arr1.length;i++)
{
if(!hmap.containsKey(arr1[i]))
hmap.put(arr1[i],1);
else
hmap.put(arr1[i],hmap.get(arr1[i])+1);
}
for(int j=0; j < arr2.length ; j++)
{
if(arr1[j]==arr2[j])
{
count1++;
hmap.put(arr1[j],hmap.get(arr1[j])-1);
}
}
for(int j=0; j < arr2.length ; j++)
{
if(arr1[j]!=arr2[j] && hmap.containsKey(arr2[j]) && hmap.get(arr2[j])!=0)
{
hmap.put(arr2[j],hmap.get(arr2[j])-1);
count2++;
}
}

result.append(count1);
result.append('A');
result.append(count2);
result.append('B');
return  result.toString();
}
return null;
}
}```````

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