# C++ priority_queue solution

• Using prime numbers and the already generated ugly numbers to generate new ugly numbers, the same idea as the previous ugly number problems. Keep track of which ugly number to use for each prime number.

The priority_queue uses 'less' as default comparator and is implemented as a max heap as default. We have to override it as a min heap.

``````//Record the maximun prime factor of each ugly number, and only multiply
//  it by the prime factor which is not less than the prime factor of the
//  ugly number. So we can avoid duplicates.
class Solution
{
//val, idx, prime factor
//  val: the candidate ugly number
//  idx: the index of the ugly number in res that is gonna to be multiplied
//  prime factor: the prime factor of the candidate ugly number.
using TIII = tuple<int, int, int>;
private:
class myGreater
{
public:
bool operator()(TIII &a, TIII &b) {return get<0>(a) > get<0>(b);}
};
public:
int nthSuperUglyNumber(int n, vector<int>& primes)
{
priority_queue<TIII, vector<TIII>, myGreater> pq;
vector<int> res(n, 1), max_factor(n, 1);
res[0] = 1;

for (auto &p : primes)
pq.push(make_tuple(p, 1, p));

for(int idx = 1; idx < n;)
{
auto tmp = pq.top();
pq.pop();
res[idx] = get<0>(tmp);
max_factor[idx++] = get<2>(tmp);
while (max_factor[get<1>(tmp)] > get<2>(tmp)) get<1>(tmp)++;
pq.push(make_tuple(res[get<1>(tmp)] * get<2>(tmp), get<1>(tmp) + 1, get<2>(tmp)));
}
return res.back();
}
};``````

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