As I know, if the count of the vector is Even, the method of robber are two.

ex:

if the count is 4, a0,a1,a2,a3,

so there are two method to robber, one is about a0,a2, the other one is about a1,a3.

if the count is 4, a0,a1,a2,a3,a4,s5

so there are two method to robber, one is about a0,a2,a4 the other one is about a1,a3,a5, right?

I write code like(key section):

```
if(!(size&0x01))
{
int count = size>>1;
int sum1 = 0,sum2 = 0;
for(int j=0;j<count;++j)
{
sum1+=nums[j*2];
sum2+=nums[j*2+1];
}
return sum1>sum2?sum1:sum2;
}
```

i think this code is same with my analysis.

But , for test case "1,2,3,4,5,1,2,3,4,5". the expected answer is 16?!

There are two robber way,1~3~5~2~4 and 2~4~1~3~5,all the sum is 15

How can we get 16 ?

Tks!