The idea is to use one hash set to record sum of every digit square of every number occurred. Once the current sum cannot be added to set, return false; once the current sum equals 1, return true;

```
public boolean isHappy(int n) {
Set<Integer> inLoop = new HashSet<Integer>();
int squareSum,remain;
while (inLoop.add(n)) {
squareSum = 0;
while (n > 0) {
remain = n%10;
squareSum += remain*remain;
n /= 10;
}
if (squareSum == 1)
return true;
else
n = squareSum;
}
return false;
}
```