32 ms C++ 4 line solution


  • 5
    L
    int missingNumber(vector<int>& nums) {
            
            int size = nums.size(),sum=0;
    
            for(int i=0;i<size;i++)
                sum += nums[i];
    
            return ((size)*(size+1)/2 - sum);
        }

  • 0
    W

    Same solution here. Took advantage of the rules.
    Not quite pertinent, but it works. : )


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