```
class Solution {
public:
int dp[10000][10000];
int MAX=1000000;
int jump(int A[], int n)
{
if(n==0) return 0;
for(int i=0;i<=n-1;i++)
dp[i][i]=0;
for(int l=2;l<=n;l++)//chain length
{
for(int s=0;s<=n-1;s++)//start indx
{
int e=s+l-1;
if(e>n-1)
break;
if(A[s]>=l-1)//min 1
dp[s][e]=1;
else
{
int min=MAX;
for(int k=s+1;k<=e-1;k++)
{
if(min>dp[s][k]+dp[k][e])
min=dp[s][k]+dp[k][e];
}
dp[s][e]=min;
}
}
}
return dp[0][n-1];
}
};
```

The wrong case is [0], but I think it is 0 when only one element in the array, as it does not need to jump, and the first is also the last index, and my code will definitely return 0 if only one element? Does it mean it should not return 0 when only one element? Also I want to make sure that all cases will have a solution to jump to the end index.