My ACC py solution using HashTable


  • 0
    W

    Use two hash tables to store the times every letter comes and check if the letters come with the same frequency.

    class Solution(object):
    def isAnagram(self, s, t):
        """
        :type s: str
        :type t: str
        :rtype: bool
        """
        if len(s) != len(t):
            return False
        sDic = {}
        tDic = {}
        for c in s:
            sDic[c] = sDic.get(c, 0) + 1
        for c in t:
            tDic[c] = tDic.get(c, 0) + 1
        for k, v in sDic.items():
            if k not in tDic or tDic[k] != v:
                return False
        return True

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