Are there any way besides counting from the front.

  • 1


    As the question suggests, do you think there is a more efficient way besides counting the length of the list and decide the position of the node to delete from the front?

    Many thanks.

  • 0

    there is. since we're given that n is guaranteed, you know there are at least n nodes in the list; then you walk through the list until a certain condition is met, remove the node, and return the head.

  • 0

    recurse until you hit the tail, then start counting backwards from there, and delete the appropriate node.

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