Quite straightforward java O(n) time, O(1) space solution - with explanations.

  • 0
    public ListNode swapPairs(ListNode head) {
            ListNode dummy = new ListNode(0);
            dummy.next = head;
            ListNode pre = dummy;//previous nodes to two adjacent nodes.
            ListNode A, B, post;//A and B are the two adjacent nodes, post, the following one
            while(pre.next != null && pre.next.next !=null){//it is the end if there is not at least two nodes.
                A = pre.next; B = A.next; post = B.next;//initializing nodes from previous node;
                pre.next = B;
                B.next = A;
                //do not forget to point to last node
                A.next = post;
                //Let's go for another turn !
                pre = A;
            return dummy.next;

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