# My solution not getting accepted for Reverse integer

• When I run locally.
for this same input 1534236469 I am getting 0 but when its run on leetCode it says its getting output as 9646324351

`````` def reverse(self, x):
max = 2147483647
k=[]
val = 0
reminder = mod = abs(x)
while(mod >= 1 or reminder >= 1):
mod = reminder % 10
reminder = int(reminder / 10)
if(mod != reminder):
k.append(mod)
val = ''.join(str(i) for i in k)
if(x < 0):
val = "-"+str(val)
if(val == ''):
val = 0
m = int(val)
if(m > max):
print(int(0))
else:
print(m)
return m``````

• You're probably getting 9646324351 locally as well. Ignore your debugging prints, the true output and the only thing that matters is the return value.

• I got same issue with you.

Input: 1534236469 Output: 9646324351 Expected: 0

then i checked the spoilers with this line:

Did you notice that the reversed integer might overflow? Assume the input is a 32-bit integer, then the reverse of 1000000003 overflows. How should you handle such cases?

then AC

``````class Solution:
# @param {integer} x
# @return {integer}
def reverse(self, x):
flag = False
if x < 0:
flag = True
elif x == 0:
return 0

min = -2147483648
max = 2147483647
s = str(abs(x))[::-1]
for i in range(len(s)):
if s[i] != '0':
r = 0-int(s[i::]) if flag == True else int(s[i::])
if r > max or r < min:
return 0
else:
return r``````

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