JAVA SOLUTION using binary search

  • 0

    public class Solution {
    public boolean search(int[] nums, int target) {

        int length = nums.length;
        return check(nums, 0,length-1, target);
    public boolean check(int[] nums, int start, int end, int target)
        if(start > end)
            return false;
        int mid = (start + end)/2;
        if(nums[mid] == target)
            return true;
        return check(nums, start, mid-1,target) || check(nums, mid+1, end, target);


  • 4

    This is average O(n), although the worst case is O(n) for any implementation. You have to abandon half if you want to get average O(logn)

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