# Python Solution for Reverse Integer with no overflow handling

• This is my code:

``````class Solution:
# @param {integer} x
# @return {integer}
def reverse(self, x):
arr = []
f = False
if x < 0:
x *= -1
f = True
while True:
arr.append(x % 10)
x /= 10
if x == 0:
break
result = 0
for i in arr:
result = i + 10 * result
if f:
result *= -1
return result
``````

Actually python wouldn't overflow, but the test cases consider it.
When Input is1534236469 and my output is 9646324351,it says wrong.:-(

• I had the same issue in JS, i had to add an if statement that checked if the number was over 2147483647 and return 0 if so.

• I have the same problem.
If you treat it like string, the reverse would never overflow.

• I had same annouing issue, althoug the code I used was way shorter than yours. I agree it is annoying.

``````    if x>=0:
test=str(x)
test2=test[::-1]
else:
test=str(abs(x))
test=test+('-')
test2=test[::-1]

return int(test2)``````

• @Lexa_Ville Just to add. If I add this condition at the end of my code it is accepted:

``````if int(test2)>2147483647:
test2='0'
if int(test2)<-2147483648:
test2='0'``````

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