# My java solution

• //One island means one tree, the question is equal to find how many trees in the 2D grids.
public int numIslands(char[][] grid) {
if (grid.length == 0 || grid == null) {
return 0;
}
int count = 0;
boolean[][] marked = new boolean[grid.length][grid[0].length];

for (int i = 0; i < grid.length; i++) {
for (int j = 0; j < grid[0].length; j++) {
if (!marked[i][j] && grid[i][j] == '1') {
dfs(grid, marked, i, j);
count++;
}
}
}

return count;

}
//depth first search
public void dfs(char[][] grid, boolean[][] marked, int i, int j) {
//out of bound
if (i < 0 || j < 0 || i >= grid.length || j >= grid[0].length) {
return;
}
//visited return
if (marked[i][j]) {
return;
}
//1 mark, 0 return
if (grid[i][j] == '1') {
marked[i][j] = true;
} else {
return;
}
//left
dfs(grid, marked, i-1, j);
//right
dfs(grid, marked, i+1, j);
//up
dfs(grid, marked, i, j-1);
//down
dfs(grid, marked, i, j+1);
}

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