# My C++ solution with two pointers (easy to understand)

• Here is my C++ solution with two pointers a,b which represent begin and end respectively.

In each loop, check whether sum is bigger than target.

If sum is bigger, then update the min_len and move begin pointer to right
else move end pointer to right.

Here is the code:

``````int minSubArrayLen(int target, vector<int>& nums) {
if(nums.empty()) return 0;
int a = -1;//begin pointer,at the first, it should be -1
int b = -1;//end pointer
int len = INT_MAX;//store the min len of the subarray
int sum = 0;//sum
// go until b reach to the end of the array
while(b < (int)nums.size()){
//if sum is smaller, then move b to the right, adds nums[b] to get the new sum
if(sum<target){
b++;
sum += nums[b];
}
//if sum is bigger, then move a to the right, minus nums[a] to get the new sum
//at the same time, update the min_len
else{
len = min(len,b-a+1);
sum -= nums[a];
a++;
}
}
return len == INT_MAX? 0 : len;//if not found, change len from INT_MAX to 0;
}``````

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