Python one line solution

  • 0
    class Solution:
    # @param {integer[]} digits
    # @return {integer[]}
    def plusOne(self, digits):
    return [int(x) for x in str(int(''.join("%s" % el for el in digits))+1)]

  • 0

    Yep, I come out the similar solution.

    return [int(c) for c in str(int(''.join([str(i) for i in digits])) + 1)]

    But I would like to know if there is any limitation for this way. Thanks.

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