**Introduction**

**QUESTION:**

We are given a number n, and we have to output the numbers from 1 to n , with the followin exceptions, if number is divisible by 3, that number should be replaced by Fizz, if that number is divisible by 5 that number should be replaced by Buzz, and if the number is divisible by both 3 & 5, we have to replace that number by FizzBuzz.

**Keypoints :**

The expected return type is a List of strings. So if n = 1, and you return an int [1] , it is wrong , it has to be ["1"].

A number N is divisible by another number M , if N%M is 0. % is the modulus. N%M returns the remainder.

**Conditions :**

N% 3 == 0

N%5 == 0

N%5 and N%3 == 0

N%5 and N%3 != 0

**Return type :**

List[str]

**Tips :**

convert int to string before appending.

**APPROACH:**

Save Fizz , Buzz and FizzBuzz as strings to three variables

First check if the number is not divisible by both 3 and 5, and if that is the case convert our i to a str and append it to our list.

Then check remaining conditions.

**SOLUTION:**

```
def fizzBuzz(self, n):
"""
:type n: int
:rtype: List[str]
"""
my_list =[]
a = "Fizz"
b = "Buzz"
c = "FizzBuzz"
for i in range(1,n+1):
k=str(i)
if i%3!=0 and i%5!=0:
my_list.append(k)
elif i%5==0 and i%3==0:
my_list.append(c)
elif i%3==0:
my_list.append(a)
elif i%5==0:
my_list.append(b)
return my_list ```
A simple and straightforward solution.
FizzBuzz is supposed to be a very famous question that is used to frequently separate non programmers from programmers.
Approach 2:
Conclusion :
![alt text](http://wwwcdn.printmag.com/wp-content/uploads/APPYFIZZ_2016_10_new-600x371.jpg)
Appy fizz is a very popular drink in India.
```