Simple and Quick 7 lines one round solution

  • 0
    // A[0]...A[l0] are all 0, A[l0+1]...A[l1] are all 1, A[l1+1]... are all 2, 
     //if A[i]==0 then we need to check if 1 has appeared or not by if(l1>=l0)
    void sortColors(int A[], int n) {
        int l0=-1, l1=-1;
        for(int i=0; i<n; ++i){
            if(A[i]==1) swap(A[++l1],A[i]);
                if(l1>=l0) swap(A[++l1],A[i]);
                else l1=l0;

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