# Python 3 solution:

• 4 steps:
1.Find the first character which is not space, the rest of string store in str2.
2.Check if the character is '+' or '-', store it in indicator.
3.Calculate the following character until the one is not in 0-9.
4.Return the result
.
'''
class Solution:
def myAtoi(self, str):

``````    INT_MAX = 2147483647
INT_MIN = -2147483648
indicator = 1
result = 0
firstNotSpaceIndex = 0
for firstNotSpaceIndex, i in enumerate(str):
if i != ' ':
break
str2 = str[firstNotSpaceIndex:]
for index, i in enumerate(str2):
if i == '+' or i == '-':
if i == '-':
indicator = -1
if index < len(str2) - 1:
index += 1
else:
return 0
while str2[index] >= '0' and str2[index] <= '9':
result = result*10 + (int(str2[index]));
if result*indicator >= INT_MAX:
return INT_MAX
if result*indicator <= INT_MIN:
return INT_MIN
if index < len(str2) - 1:
index += 1
else:
break
break
return result*indicator
``````

'''

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