Easy Python solution

  • 0
    class Solution:
        def reverse(self, x):
            :type x: int
            :rtype: int
            if x<0:
                return -self.reverse(-x)
            new_num = 0
            while x:
                new_num = x%10 + new_num*10
                x = x//10
            if new_num>2147483647:
                return 0
            return new_num

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