Java solution


  • 0
    W

    If we find a leaf node, we juage whether it meets the condition. If it is not a leaf node, we juage whether it exists a leaf node that meets the condition in its left child tree,then go to its right child tree.

     public boolean hasPathSum(TreeNode root, int sum) {
            if(root==null) return false;
            else if(root.left==null&&root.right==null) return sum == root.val;
            if(hasPathSum(root.left, sum-root.val)) return true;
            if(hasPathSum(root.right, sum-root.val)) return true;
            return false;
        }
    

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