Solution in Java for ReverseInt


  • 0
    P
    class Solution {
        public int reverse(int x) {
            int r = 0;
            int count = 1;
            try { 
                
            int x1 = Math.abs(x);
            while ( x1 > 0){
                int a = x1%10;
                
                
                if(count > 9){
    	            	if(r == 214748364 && a>7)
    	            		r=0;
    	            	
    	            	if(r > 214748364 && a>0){
    	            		r=0;
    	            		break;
    	            	}
    	            	
    	            	
    	            }
                
                r = r * 10 + a;
                x1 = x1/10;
                count++;
                
                
            }
            
            if(x < 0)
                r = -r;
                
                
            // 2147483643
            // 32bit int - 2147483648
            
            } catch (Exception e){
                r=0;
            }
            return r;
        }
    }
    

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