wisely use subquery and beat 98.33%

  • 0
    select sum(new.tiv_2016) as TIV_2016
    (select distinct i1.pid, i1.tiv_2016
    from insurance i1, insurance i2
    where i1.tiv_2015 = i2.tiv_2015 and i1.pid != i2.pid and not exists
    (select *
    from insurance i3
    where i1.lat = i3.lat and i1.lon = i3.lon and i1.pid != i3.pid)
     ) as new

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