# Both recursive and iterative solution Python with comments

• ``````# Definition for a binary tree node.
# class TreeNode(object):
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None

class Solution(object):
def postorderTraversal(self, root):
"""
:type root: TreeNode
:rtype: List[int]
"""
# Basic idea behind this is that we use two stacks
# One get the element as we traverse and other stores the order
# So what we want in postorder is that first we have to print left most side then right most side and root
# so in first stack order will be left right
# in second stack pop one element from first stack put into second stack and put left and right for that elem in first stack
# So basically we are storing element that will print last in second stack first and so forth
# To get better understanding first draw tree and write down post order traversal check from end to start pattern

#return self.recursive_traverse(root, [])
return self.iterative_traverse(root)

def iterative_traverse(self, current):
if current == None:
return []
entry_stack = []
result_stack = []
entry_stack.append(current)
while len(entry_stack) != 0:
node = entry_stack.pop()
if node.left:
entry_stack.append(node.left)
if node.right:
entry_stack.append(node.right)
result_stack.append(node.val)
return(list(reversed(result_stack)))

def recursive_traverse(self, current, result):
if current:
self.recursive_traverse(current.left, result)
self.recursive_traverse(current.right, result)
result.append(current.val)
return result
else:
return []

``````

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