Simple Java Solution

  • 0
    class Solution {
        public int[] constructRectangle(int area) {
            int sqrt =(int)Math.floor(Math.sqrt(area));
            int[] ans = {area/sqrt,sqrt};
            return ans;

    The difference in length and breadth would be smallest for sqrt, but if the area is not a perfect square we try the nearest number smaller than the sqrt, that would divide the area.

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